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Find the roots of the quadratic polynomial \( \mathrm{t}^{2}-15 \).
Given:
$h(t) = t^2 – 15$
To find:
Here, we have to find the roots of h(t).
Solution:
To find the zeros of h(t), we have to put $h(t)=0$.
This implies,
$t^2 – 15 = 0$
$t^2 – \sqrt{(15)^2} = 0$
$(t+\sqrt{15})(t-\sqrt{15})= 0$ (since $a^2-b^2=(a+b) (a-b) $)
$t+\sqrt{15}=0$ and $t-\sqrt{15}=0$
$t=-\sqrt{15}$ and $t= \sqrt{15}$
Therefore, the zeros of the quadratic equation $h(t) = t^2 – 15 $ are $-\sqrt{15}$ and $\sqrt{15}$.
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