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Find the product: $ \quad $ (Using suitable property)
(a) $ 15 \times(-25) \times(-4) \times(-10) $
(b) $ 625 \times(-35)+(-625) \times 65 $
Given:
(a) \( 15 \times(-25) \times(-4) \times(-10) \) (b) \( 625 \times(-35)+(-625) \times 65 \)
To do:
We have to find the product using suitable properties.
Solution:
(a) $15 \times(-25) \times(-4) \times(-10)=[15\times(-10)]\times[(-25)\times(-4)]$ (On rearranging and using Associative law)
$=(-150)\times100$ [$(-)\times(-)=(+)$]
$=-15000$
(b) $625 \times(-35)+(-625) \times 65=-625[35+65]$ [Taking $-625$ common and using distributive law]
$=-625\times100$
$=-62500$
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