Find the number of digit in the square root of the given number ( without any calculation): $17161$.

Given: A number $17161$.

To do: To find the number of digits in the square root of the given number $17161$.

Solution:

Given number is $17161$

Number of the digits in the given number $n=5(odd)$

If , $n$ is odd, then number of digits in the square root of the number$=\frac{n+1}{2}$

$=\frac{5+1}{2}$

$=\frac{6}{2}$

$=3$

Thus, there are $3$ digits in the square root of the given number $17161$.
 

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Updated on: 10-Oct-2022

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