Find the nature of roots:$6k+\frac{17}{k} = \frac{29}{2}$
Given :
The given expression is $6k+\frac{17}{k} = \frac{29}{2}$.
To find :
We have to find the nature of the roots.
Solution :
$6k+\frac{17}{k} = \frac{29}{2}$
$6k(k)+17= \frac{29}{2} (k)$
$2(6k^2)+17(2) = 29k$
$12k^2+34=29k$
$12k^2-29k+34=0$
Discriminant $= (-29)^2-4(12)(34)$
$= 841-1632$
$= -791<0$
Therefore, the given equation does not have real roots.
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