![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Find the missing frequencies in the following distribution, if the sum of the frequencies is 120 and the mean is 50.
Class: | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 |
Frequency: | 17 | $f_1$ | 31 | $f_2$ | 19. |
Given:
The sum of the frequencies is 120 and the mean is 50.
To do:
We have to find the missing frequencies.
Solution:
Let the assumed mean be $A=50$.
Class size $h=20$
$\sum{f_i}=68+f_1+f_2$
$\Rightarrow 120=68+f_1+f_2$
$\Rightarrow 120-68=f_1+f_2$
$\Rightarrow f_1=52-f_2$..........(i)
Mean $=A+h \times \frac{\sum{f_iu_i}}{\sum{f_i}}$
Therefore,
Mean $50=50+20\times(\frac{4+f_2-f_1}{68+f_1+f_2})$
$50-50=20\times\frac{4+f_2-f_1}{68+f_1+f_2}$
$\frac{4+f_2-f_1}{68+f_1+f_2}=0$
$4+f_2-(52-f_2)=0$ [From (i)]
$2f_2=48$
$f_2=24$
$\Rightarrow f_1=52-24=28$
The missing frequencies $f_1$ and $f_2$ are 28 and 24 respectively.
Advertisements