Find the median of 3, 11, 7, 2, 5, 9, 9, 2, 10.
Given :
The given numbers are 3, 11, 7, 2, 5, 9, 9, 2, 10.
To do :
We have to find the median.
Solution :
Median:
The median of a set of numbers is the middle number in the set (after the numbers have been arranged from least to greatest) or, if there are even numbers in the given data, the median is the average of the middle two numbers.
3, 11, 7, 2, 5, 9, 9, 2, 10.
Arranging the numbers in ascending order,
2, 2, 3, 5, 7, 9, 9, 10, 11.
There are odd numbers in the given data.
Therefore,
Median $=$ Middle number in the given data set
Therefore, the median is 7.
Related Articles Find the product:$(i)$. $\frac{9}{2}\times(-\frac{7}{4})$$(ii)$. $\frac{3}{10}\times(-9)$$(iii)$. $-\frac{6}{5}\times\frac{9}{11}$$(iv)$. $\frac{3}{7}\times(-\frac{2}{5})$$(v)$. $\frac{3}{11}\times\ \frac{2}{5}$$(vi)$. $\frac{3}{-5}\times(-\frac{5}{3})$
Find the value of:$(i)$. $2^6$$(ii)$. $9^3$$(iii)$. $11^2$$(iv)$. $5^4$
(7/9)^2 ÷(14/3)^2
 Find $\frac{2}{7}\times\frac{5}{9}$ a) Is $\frac{2}{7}\times\frac{5}{9}$= $\frac{5}{9}\times\frac{2}{7}$ b) Is $\frac{2}{7}\times\frac{5}{9}$ > or$\frac{5}{9}\times\frac{2}{7}$?
Simplify:\( 2 \frac{3}{11}+\frac{9}{-11} \)
Without adding, find the sum.(i) \( 1+3+5+7+9 \)(ii) \( 1+3+5+7+9+11+13+15+17+19 \)(iii) \( 1+3+5+7+9+11+13+15+17+19+21+23 \)
Solve the following:$3(5 z-7)-2(9 z-11)=4(8 z-13)-17$.
Solve:(i) $3-\frac{2}{5}$(ii) $4+\frac{7}{8}$(iii) $\frac{3}{5}+\frac{2}{7}$(iv) $\frac{9}{11}-\frac{4}{15}$(v) $\frac{7}{10}+\frac{2}{5}+\frac{3}{2}$(vi) $2\frac{2}{3}+3\frac{1}{2}$(vii) $8\frac{1}{2}-3\frac{5}{8}$
Re-arrange suitably and find the sum in each of the following:(i) \( \frac{11}{12}+\frac{-17}{3}+\frac{11}{2}+\frac{-25}{2} \)(ii) \( \frac{-6}{7}+\frac{-5}{6}+\frac{-4}{9}+\frac{-15}{7} \)(iii) \( \frac{3}{5}+\frac{7}{3}+\frac{9}{5}+\frac{-13}{15}+\frac{-7}{3} \)(iv) \( \frac{4}{13}+\frac{-5}{8}+\frac{-8}{13}+\frac{9}{13} \)(v) \( \frac{2}{3}+\frac{-4}{5}+\frac{1}{3}+\frac{2}{5} \)(vi) \( \frac{1}{8}+\frac{5}{12}+\frac{2}{7}+\frac{7}{12}+\frac{9}{7}+\frac{-5}{16} \)
-5[6 ÷ 3 x (-2)] - [9 - (-5) x 2]
Observe the following pattern$1 + 3 = 2^2$$1 + 3 + 5 = 3^2$$1+3 + 5 + 7 = 4^2$and write the value of $1 + 3 + 5 + 7 + 9 +…………$ upto $n$ terms.
Without adding, find the sum of the following:$1+3+5+7+9+11+13$
Find the sum:$(i)$. $\frac{5}{4}+(-\frac{11}{4})$$(ii)$. $\frac{5}{3}+\frac{3}{5}$$(iii)$. $\frac{-9}{10}+\ \frac{22}{15}$$(iv)$. $\frac{-3}{11}+\frac{5}{9}$$(v)$. $\frac{-8}{19}+(-\frac{2}{57})$$(vi)$. $-\frac{2}{3}+0$$(vii)$. $-2\frac{1}{3}\ +\ 4\frac{3}{5}$
Find the mode of the following data: 3, 5, 7, 4, 5, 3, 5, 6, 8, 9, 5, 3, 5, 3, 6, 9, 7, 4.
Find the mode of the following data: 3, 3, 7, 4, 5, 3, 5, 6, 8, 9, 5, 3, 5, 3, 6, 9, 7, 4.
Kickstart Your Career
Get certified by completing the course
Get Started