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Find the least number with four digits which is a perfect square
To do: To find the least number with four digits which is a perfect square.
Solution:
The least $4$ digit number$=1000$
Since, $( 31)^2<1000$
We take, the next perfect square number i.e., $(32)^2= 1024$
$\therefore 1024$ is the required least number $4$ digit number which is a perfect square.
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