Find the indicated terms in each of the following sequences whose nth terms are:
$ a_{n}=n(n-1)(n-2) ; a_{5} $ and $ a_{8} $

Given:

$a_{n}=n(n-1)(n-2)$

To do:

We have to find $a_{5}$ and $a_{8}$.

Solution:

 To find $a_{5}$, we have to substitute $5$ in place of $n$ in $a_{n}=n(n-1)(n-2)$.

This implies,

$a_{5}=5(5-1)(5-2)$

$=5(4)(3)$

$=60$.

 To find $a_{8}$, we have to substitute $8$ in place of $n$ in $a_{n}=n(n-1)(n-2)$.

This implies,

$a_{8}=8(8-1)(8-2)$

$=8(7)(6)$

$=336$.

Therefore, $a_{5}=60$ and $a_{8}=336$.

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Updated on: 10-Oct-2022

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