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Find the height of a trapezium, the sum of lengths of whose bases is $39cm$, and whose area is $65cm^2.$
Given: The sum of lengths of trapezium's bases is $39cm$, and whose area is $65cm^2.$
To do: Find the height of the trapezium
Solution:
Given the area of trapezium = 65 sq cm
Sum of bases = $ (base1 + base2) = 39$ cm
The formula for Area of trapezium
=$\frac{1}{ 2} \times height(base1 + base2)$
= $\frac{1}{2} \times h \times 39 = 65$
h = $65 x \frac{2}{39} = \frac{10}{3}$
height = $\frac{10}{3} cm = 3 \frac{1}{3}$ cm
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