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Find the HCF of 522,812,1276.
Given :
The given numbers are 522, 812, 1276
To do :
We have to find the HCF of the given numbers.
Solution :
By Euclid's division algorithm,
$$Dividend = Divisor \times Quotient + Remainder$$
Here, $1276 > 812 > 522$
So, apply Euclid's division lemma for 1276 and 812
$1276 = 812 \times 1 + 464$
Remainder $=464$
Repeat the above process until we will get 0 as the remainder.
Now, consider 812 as the dividend and 464 as the divisor,
$812 = 464 \times 1 + 348$
Remainder $=348$
Now, consider 464 as the dividend and 348 as the divisor,
$464 = 348 \times 1+ 116$
Remainder $=116$
Now, consider 348 as the dividend and 116 as the divisor,
$348 = 116 \times 3 + 0$
Remainder $=0$
So, HCF of 1276 and 812 is 116.
Now, apply Euclid's division lemma for 522 and 116,
$522 = 116 \times 4 + 58$
Remainder $=58$
Now, consider 116 as the dividend and 58 as the divisor,
$116 = 58 \times 2 + 0$
Remainder $=0$
Therefore, HCF of 1276, 812, and 522 is 58.