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Find the greatest number of three digits which is a perfect square.
To do:
We have to find the greatest three digit number which is a perfect square.
Solution:
The greatest $3$ digit number$=999$
Square root of 999 is,
31 | |
3 | 999 9 |
61 | 99 61 |
38 |
The remainder is 38.
Therefore, if we subtract 38 from 999 then the new number will be a perfect square.
The required number is $999-38$
$=961$
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