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Find the following products:
$-11y^2 (3y + 7)$
Given:
$-11y^2 (3y + 7)$
To do:
We have to find the given product.
Solution:
$-11y^2 (3y + 7)=-11y^2 \times 3y - 11y^2 \times 7$
$= -33y^{2+1}-77y^2$
$= -33y^3-77y^2$
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