Find the following product.
$ \left(\frac{-2}{7} a^{4}\right) \times\left(\frac{-3}{4} a^{2} b\right) \times\left(\frac{-14}{5} b^{2}\right) $

Given:

\( \left(\frac{-2}{7} a^{4}\right) \times\left(\frac{-3}{4} a^{2} b\right) \times\left(\frac{-14}{5} b^{2}\right) \)

To do:

We have to find the given product.

Solution:

$(\frac{-2}{7} a^{4}) \times(\frac{-3}{4} a^{2} b) \times(\frac{-14}{5} b^{2})=(\frac{-2}{7}) \times(\frac{-3}{4})\times(\frac{-14}{5}) \times a^{4} \times a^{2} \times b \times b^{2}$

$=\frac{-3}{5} a^{4+2} \times b^{1+2}$

$=\frac{-3}{5} a^{6} b^{3}$

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Updated on: 10-Oct-2022

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