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Find the following product and reduce them to the lowest form (If possible):
$ 3 \frac{8}{19} \times 5 \frac{3}{7} \times3 \frac{10}{13}$
To do: Find the following product and reduce them to the lowest form
Solution:
$ 3 \frac{8}{19} \times 5 \frac{3}{7} \times3 \frac{10}{13}$
Convert the mixed fractions into improper fraction first
$3\frac{8}{19}=\frac{65}{19}$
$5 \frac{3}{7}= \frac{38}{7} $
$3 \frac{10}{13}=\frac{49}{13}$
Now ,
$\frac{65}{19}\times \frac{38}{7}\times \frac{49}{13} $
$\frac{5}{1}\times \frac{2}{1}\times \frac{7}{1} $
[$7\times 7 =49 and 13\times 5 =65\ and \ 19\times2 $]
=$70$
Therefore the answer is $70$
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