Find The first four terms of an AP, whose first term is $–2$ and the common difference is $–2$.
Given: First term, $a=-2$ and common difference, $d=-2$.
To do: To find first four terms of the A.P.
Solution:
As given, First term$( a)=-2$
Common difference$( d)=-2$
$\therefore\ 2^{nd}$ term$=a+d=-2-2=-4$
$\Rightarrow\ 3^{rd}$ term$a+2d=-2+2( -2)=-6$
$\Rightarrow\ 4^{th}$ term $a+3d=-2+3( -2)=-8$
Therefore, the A.P. is $-2,\ -4,\ -6,\ -8,$ ......
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