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Find the distance of the point $( 6,\ -8)$ from the origin.
Given: Point $( 6,\ -8)$.
To do: To find the Distance of the point $( 6,\ -8)$ from the origin.
Solution:
As given, $x_1=0,\ y_1=0,\ x_2=6,\ y_2=-8$
$\therefore$ Distance of the point $( 6,\ -8)$ from the origin $=\sqrt{( x_2-x_1)^2+( y_2-y_1)^2}$
$=\sqrt{ ( 6-0)^2+( -8-0)^2}$
$=\sqrt{36+64}$
$=\sqrt{100}$
$=10\ units$
Thus, distance of the point from the origin is $10\ units$
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