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Find the distance of $( -3,\ 4)$ from the $x-$axis.
Given: Point $( -3,\ 4)$.
To do: To find the distance of $( -3,\ 4)$ from the $x-$axis.
Solution: To find the distance of $( -3,\ 4)$ from the $x-$axis means to find the distance of $( -3,\ 4)$ from $( -3,\ 0)$.
Using distance formula,
Distance between the two point ${=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}}$
Distance of $( -3,\ 4)$ from $( -3,\ 0)=\sqrt{( -3-( -3))^{2}+( 0-4)^{2}}$
$=\sqrt{0+16}$
$=\pm4$
$\because$ Distance can't be negative, therefor we reject the value $-4$.
$\therefore$ Required distance of $( -3,\ 4)$ from the $x-$axis is $4$ unit.
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