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Find the derivative of $V=2x^3+3x+9$.
Given:
$V=2x^3+3x+9$.
To do:
We have to find the derivative of $V=2x^3+3x+9$.
Solution:
Let $f(x)=2x^3+3x+9$
$f'(x)=\frac{d(2x^3+3x+9)}{dx}$
$=2(3)x^{3-1}+3x^{1-1}+0$
$=6x^2+3x^0$
$=6x^2+3$
The derivative of $V=2x^3+3x+9$ is $6x^2+3$.
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