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Find the curved surface area of a cone with base radius $5.25\ cm$ and slant height $10\ cm$.
Given:
The base radius of a cone is $5.25\ cm$ and the slant height is $10\ cm$.
To do:
We have to find the curved surface area of the cone.
Solution:
Radius of the base of the cone $(r) = 5.25\ cm$
Slant height of the cone $(l) = 10\ cm$
Therefore,
Curved surface area of the cone $= \pi rl$
$=\frac{22}{7} \times 5.25 \times 10$
$=\frac{22 \times 52.5}{7}$
$=22 \times 7.5$
$=165 \mathrm{~cm}^{2}$
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