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Find the cubes of the following numbers:
(i) 7
(ii) 12
(iii) 16
(iv) 21
(v) 40
(vi) 55
(vii) 100
(viii) 302
(ix) 301.
To do:
We have to find the cubes of the given numbers.
Solution:
(i) $7^3=7\times7\times7$
$=49\times7$
$=343$
(ii) $(12)^3=12\times12\times12$
$=144\times12$
$=1728$
(iii) $(16)^3=16\times16\times16$
$=256\times16$
$=4096$
(iv) $(21)^3=21\times21\times21$
$=441\times21$
$=9261$
(v) $(40)^3=40\times40\times40$
$=1600\times40$
$=64000$
(vi) $(55)^3=55\times55\times55$
$=3025\times55$
$=166375$
(vii) $(100)^3=100\times100\times100$
$=10000\times100$
$=1000000$
(viii) $(302)^3=302\times302\times302$
$=91204\times302$
$=27543608$
(ix) $(301)^3=301\times301\times301$
$=90601\times301$
$=27270901$
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