Find the area of the below figure, in square cm, correct to one place of decimal. (Take $ \pi=22 / 7 $ )
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To do:
We have to find the area of the given figure, in square cm, correct to one place of decimal.
Solution:
Join $AD$
$ABCD$ is a square.
Length of each side of the square $= 10\ cm$
Area of the square $=(10)^2 = 100\ cm^2$
Radius of the semi-circle $=\frac{10}{2}=5\ cm$
Area of the semi-circle $=\frac{1}{2} \pi r^{2}$
$=\frac{1}{2} \times \frac{22}{7} \times 5 \times 5$
$=\frac{275}{7}$
$=39.28 \mathrm{~cm}^{2}$
Therefore,
Total area of the figure $=100-24+39.28$
$=76+39.28$
$=115.28 \mathrm{~cm}^{2}$
$=115.3 \mathrm{~cm}^{2}$
The area of the given figure is $115.3\ cm^2$.
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