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Find the area of a rhombus whose diagonals are:$14.8\ cm,\ 12.5\ cm$.
Given: Diagonals of the rhombus are:$14.8\ cm,\ 12.5\ cm$.
To do: To find the area of a rhombus.
Solution:
Area of rhombus$=\frac{1}{2}\times d_1\times d_2$
$=\frac{1}{2}\times14.8\times12.5$
$=\frac{1}{2}\times185$
$=\frac{185}{2}$
$=92.5\ cm^2$
Thus, the area of the rhombus is $92.5\ cm^2$.
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