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Find HCF of the following
$x^2- 1, x^2 + 2^x - 3, x^2- 3x + 2$
Given: $x^2- 1, x^2 + 2^x - 3, x^2- 3x + 2$
To do: Find HCF
Solution:
$x^{2}-1, x^{2}+2x-3, x^{2}-3x+2$
=$x^{2}-1 = (x + 1)(x - 1)$
=$x^{2} + 2x - 3$
= $x^{2} + 3x - x - 3 = (x - 1) (x + 3)$
=$x^{2} - 3x + 2$
=$ x^{2} - 3x + 2 = x^{2} - 2x - x + 2$
=$ (x - 1) (x - 2)$
From the above, the HCF of given expressions is $(x-1)$
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