Find $\angle ABC=?$
"
Given: A trapezium $ABCD$ in the figure.
To do: To find $\angle ABC=?$
Solution:
As given, In trapezium $ABCD,\ AB||CD$
And $BC$ and $AD$ are non parallel.
The sum of the two adjacent angles is equal to $180^o$
$\Rightarrow \angle ABC+\angle BCD=180^o$
$\Rightarrow \angle ABC+140^o=180^o$
$\Rightarrow \angle ABC=180^o-140^o=40^o$
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