Find $\angle$ABC, $\angle$BAC and $\angle$CAF
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To do: Find $\angle$ABC, $\angle$BAC and $\angle$CAF
Solution:
EF || GH the two lines are parallel
So $\angle$ ABC = 65* [Alternate angles]
angle CAE = $\angle$ACH=100* (Alternate angles)
angle BAC $+$ 65 =$\angle$CAE = $\angle$ACH = 100
So $\angle$BAC = 100 $-$ 65 = 35*
$\angle$ CAF = 180 $-$ 100 = 80* [interior angles on same side of transversal]
$\angle$ ABC = 65*
$\angle$BAC = 35*
$\angle$CAF = 80*
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