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Find ' $ a $ ' so that the statement becomes true
(i) $ 37+59=59+a $
(ii) $ 43+a=48+43 $
(iii) $ (43+a)+77=43+(95+77) $
(iv) $ (4+11)+17=(4+a)+11 $
Given:
(i) \( 37+59=59+a \)
(ii) \( 43+a=48+43 \)
(iii) \( (43+a)+77=43+(95+77) \)
(iv) \( (4+11)+17=(4+a)+11 \)
To do:
We have to find the values of $a$.
Solution:
(i) $37+59=59+a$
$\Rightarrow a=37+59-59$
$\Rightarrow a=37$
(ii) $43+a=48+43$
$\Rightarrow a=48+43-43$
$\Rightarrow a=48$
(iii) $(43+a)+77=43+(95+77)$
$\Rightarrow 43+a+77=43+95+77$
$\Rightarrow a=95+43-43+77-77$
$\Rightarrow a=95$
(iv) $(4+11)+17=(4+a)+11$
$\Rightarrow 4+11+17=4+a+11$
$\Rightarrow a=4-4+11-11+17$
$\Rightarrow a=17$
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