![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Find a natural number whose square diminished by 84 is equal to thrice of 8 more than the given number.
Given:
A natural number whose square diminished by 84 is equal to thrice of 8 more than the given number.
To do:
We have to find the number.
Solution:
Let the required natural number be $x$.
According to the question,
$x^2-84=3(x+8)$
$x^2-84=3x+24$
$x^2-3x-84-24=0$
$x^2-3x-108=0$
Solving for $x$ by factorization method, we get,
$x^2-12x+9x-108=0$
$x(x-12)+9(x-12)=0$
$(x+9)(x-12)=0$
$x+9=0$ or $x-12=0$
$x=-9$ or $x=12$
$-9$ is not a natural number. Therefore, the value of $x$ is $12$.
The required natural number is $12$.
Advertisements