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Factorize x2-12 y2-2xy+ 6xy
Given: $x^2-12 y^2-2xy+ 6xy
To Do: Factorize the above number.
Answer:
$x^2-12 y^2-2xy+ 6xy$
=$x^2-2xy+6xy-12y^2$
= $x(x - 2y) + 6y(x -2y)$
= $(x + 6y)(x - 2y)$
So , $x^2-12 y^2-2xy+ 6xy$
= $(x + 6y)(x - 2y)$
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