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Factorize:$ x\left(x^{3}-y^{3}\right)+3 x y(x-y) $
Given :
\( x\left(x^{3}-y^{3}\right)+3 x y(x-y) \)
To do :
We have to factorize the given expression.
Solution :
$x(x^3 – y^3) + 3xy(x – y) = x(x – y) (x^2 + xy + y^2) + 3xy(x – y)$
$= x(x – y) (x^2 + xy + y^2 + 3y)$
Hence, $x(x^3 – y^3) + 3xy(x – y) = x(x – y) (x^2 + xy + y^2 + 3y)$.
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