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Factorize:$x^3 - 12x(x - 4) - 64$
Given:
$x^3 - 12x(x - 4) - 64$To do:
We have to factorize the given expression.
Solution:
We know that,
$(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3$
$(a - b)^3 = a^3 - b^3 - 3ab(a - b)$
Therefore,
$x^3 - 12x(x - 4) - 64 = x^3 - 12x^2 + 48x - 64$
$= (x)^3 - 3 \times x^2 \times 4 + 3 \times x \times (4)^2 - (4)^3$
$= (x - 4)^3$
$= (x - 4) (x - 4) (x - 4)$
Hence, $x^3 - 12x(x - 4) - 64 = (x - 4) (x - 4) (x - 4)$.
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