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Factorize:
$7(x-2y)^2 - 25(x-2y) +12$
Given :
$7(x-2y)^2 - 25(x-2y) +12$
To do :
We have to factorize the given expression.
Solution :
$7(x-2 y)^{2}-25(x-2 y)+12$
Let $x-2 y=a$
This implies,
$7(x-2 y)^{2}-25(x-2 y)+12=7 a^{2}-25 a+12$
$=7 a^{2}-21 a-4 a+12$
$=7 a(a-3)-4(a-3)$
$=(a-3)(7 a-4)$
Therefore,
$7(x-2 y)^{2}-25(x-2 y)+12=(x-2 y-3)[7 (x-2 y)-4]$
$=(x-2 y-3)(7x-14 y-4)$
Hence, $7(x-2 y)^{2}-25(x-2 y)+12=(x-2 y-3)(7x-14 y-4)$.
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