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Factorize:
$x^{2} \ +\ 5x\ −\ 6$
Given: $x^{2} \ +\ 5x\ −\ 6$
To do: Here we have to factorize $x^{2} \ +\ 5x\ −\ 6$.
Solution:
You need to find two digits that both add to $+$5 and multiply to $-$6. 2 and 3 are possibilities, but ultimately do not work.
∴ We'll go with -1 and +6.
$x^{2} \ +\ 5x\ −\ 6$
$=\ (x\ -\ 1)(x\ +\ 6)$
So, factorization of $x^{2} \ +\ 5x\ −\ 6$ is $(x\ -\ 1)(x\ +\ 6)$.
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