Express the following linear equations in the form $ax + by + c = 0$ and indicate the values of $a, b$ and $c$ in each case:
$-2x + 3y = 12$
Given:
$-2x + 3y = 12$
To do:
We have to express the given linear equation in the form $ax + by + c = 0$ and indicate the values of $a, b$ and $c$.
Solution:
$-2x + 3y = 12$
$\Rightarrow -2x + 3y - 12 = 0$
Comparing it with $ax+by+c=0$, we get,
$a= -2, b = 3$ and $c = - 12$.
The values of $a, b$ and $c$ are $-2, 3$ and $-12$ respectively.
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