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Express each of the following integers as a product of its prime factors.
945
Given:
Given integer is 420.
To do:
Here we have to express the given integer as a product of its prime factors.
Solution:
We know that,
Every positive integer greater than 1 can be written as a product of prime numbers (or the integer is itself a prime number). So,
- Composite number $=$ Product of prime numbers
Prime factorization of 945 is:
$945\ =\ 3\ \times\ 3\ \times\ 3\ \times\ 5\ \times\ 7$
$\mathbf{945\ =\ 3^3\ \times\ 5^1\ \times\ 7^1}$
Hence, 945 can be expressed as $3^3\ \times\ 5^1\ \times\ 7^1$.
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