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Expand $(3x-y+z)^2$.
Given :
The given expression is $(3x-y+z)^2$.
To find :
We have to expand the given expression using the suitable identity.
Solution :
We know that,
$(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca$
On comparison,
$a=3x, b=-y, c=z$
Therefore,
$(3x-y+z)^2=(3x)^2+(-y)^2+(z)^2+2(3x)(-y)+2(-y)(z)+2(z)(3x)$
$=9x^2+y^2+z^2-6xy-2yz+6xz$.
The expansion of $(3x-y+z)^2$ is $9x^2+y^2+z^2-6xy-2yz+6xz$.
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