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Evaluate the following products without multiplying directly:
(i) $ 103 \times 107 $
(ii) $ 95 \times 96 $
(iii) $ 104 \times 96 $
To do:
We have to evaluate the given products without multiplying directly.
Solution:
We know that,
$(x + a)(x+b) = x( x+ b) + a(x+b)$
$=x^2+xb+ax+ab$
$=x^2+x(a+b)+ab$
Therefore,
(i) \( 103 \times 107=(100+3) \times (100+7) \)
Here, $x=100, a=3$ and $b=7$
This implies,
$(100+3)(100+7) = (100)^2+100(3+7)+3\times7$
$=10000+100(10)+21$
$=10000+1000+21$
$=11021$
Hence, $103 \times 107=11021$.
(ii) \( 95 \times 96=(100-5)\times(100-4) \)
Here, $x=100, a=-5$ and $b=-4$
This implies,
$(100-5)(100-4) = (100)^2+100(-5-4)+(-5)\times(-4)$
$=10000+100(-9)+20$
$=10000-900+20$
$=9120$
Hence, $95 \times 96=9120$.
(iii) \( 104 \times 96=(100+4)\times(100-4) \)
Here, $x=100, a=4$ and $b=-4$
This implies,
$(100+4)(100-4) = (100)^2+100(4-4)+4\times(-4)$
$=10000+100(0)-16$
$=10000+0-16$
$=9984$
Hence, $104 \times 96 =9984$.