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Evaluate the following:$\sqrt{1} + \sqrt{4}$
Given :
The given expression is $\sqrt{1} + \sqrt{4}$.
To do :
We have to evaluate the given expression.
Solution :
We know that,
$\sqrt{a} = \pm a$
$\sqrt{1} = \pm 1$
$\sqrt{4} = \pm 2$
Therefore, $\sqrt{1}+\sqrt{4}=1+2=3$
$\sqrt{1}+\sqrt{4}=-1+(-2)=-3$
$\sqrt{1}+\sqrt{4}=-1+2=1$
$\sqrt{1}+\sqrt{4}=1+(-2)=-1$.
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