Draw the graph of the polynomial \( \mathrm{f}(\mathrm{x})=\mathrm{x}^{2}-2 \mathrm{x}-8 \).
Given:
Given polynomial is \( \mathrm{f}(\mathrm{x})=\mathrm{x}^{2}-2 \mathrm{x}-8 \).
To do:
We have to draw the graph of the given polynomial.
Solution:
Let $y =f(x)= x^2 - 2x - 8$.
The following table gives the values of $f(x)$ for various values of x.
$x$ | $-4$ | $-3$ | $-2$ | $-1$ | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ |
$f(x)$ | 16 | 7 | 0 | $-5$ | $-8$ | $-9$ | $-8$ | $-5$ | 0 | 7 |
Plot the points $(-4, 16), (-3, 7), (-2, 0), (-1, -5), (0, - 8), (1, - 9), (2, - 8), (3, - 5), (4, 0), (5, 7)$ on a graph paper and draw a curve passing through these points.
The curve so obtained represents the graph of the polynomial $f(x) = x^2 - 2x - 8$.
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