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Draw perpendicular bisectors on the three sides of PQR
"
Triangle:
(i) Draw a line segment QR = 6.5 cm.
(ii) Make ∠ XQR = 45°
(iii) Make ∠ YRQ = 75°
(iv) Let XQ and YR intersect at P.
Then ∆ PQR is the required triangle.
Perpendicular Bisectors:
(i). Take P as a centre and radius more than or equal to the line segment draw arcs on the upper and the lower half of line segment PQ
(ii). Now take Q as a centre and with same radius draw arcs on the upper and the lower half of line segment PQ. Where the arcs intersect name it A and B
(iii). Join A and B
AB is the perpendicular bisector of PQ
Repeat this for all sides of triangle.
Updated on: 10-Oct-2022
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