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Draw \( \overline{A B} \) of length \( 7.3 \mathrm{~cm} \) and find its axis of symmetry.
Given:
$\overline {AB}=7.3\ cm$.
To do:
We have to draw $AB$ of length $7.3\ cm$ and find its axis of symmetry.
Solution:
Let's first draw a line segment of length $7.3\ cm$.
1. Draw a line $l$, mark point $A$ on it.
2. Since length is $7.3\ cm$, we measure $7.3\ cm$ using ruler and compass.
3. Now keeping compass opened the same length, we keep pointed end at point A and draw an arc on line l.
So, the required line segment is $AB =7.3\ cm$.
Now, we need to find its axis of symmetry.
1. Given a line segment $AB$.
2. Now with $A$ as centre and radius more than half $AB$, draw an arc on top and bottom of $AB$.
3. Now with $B$ as the centre and same radius, draw an arc on top and bottom of $AB$.
4. Where the two arcs intersect above $AB$ is point $P$ and where the two arcs intersect below $AB$ is point $Q$.
Join $PQ$.
$PQ$ is the line of symmetry of line segment AB.
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