DL and $ B M $ are the heights on sides $ A B $ and AD respectively of parallelogram $ \mathrm{ABCD} $ (Fig 11.24). If the area of the parallelogram $ \mathrm{A} $ is $ 1470 \mathrm{~cm}^{2}, \mathrm{AB}=35 \mathrm{~cm} $ and $ \mathrm{AD}=49 \mathrm{~cm} $, find the length of $ \mathrm{BM} $"

Given:

Area of parallelogram $=1470\ cm^2$ 

$AB=35\ cm$ and $AD=49\ cm$

To do:

We have to find the length of $BM$.

Solution:

We know that,

Area of parallelogram of base b and height h $=b\times h$

This implies,

$1470=49\times BM$

$BM= \frac{1470}{49}\ cm$

$BM=30\ cm$

Therefore, the length of BM is 30 cm.

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Updated on: 10-Oct-2022

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