![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Divide the following:$9^3 + 18^2 - 9$ by $3l+3$.
Given :
The given terms are $9^3 + 18^2 - 9$ and $3l+3$.
To do :
We have to divide the given expressions.
Solution :
Dividend $=9^3 + 18^2 - 9$
Divisor $= 3l+3$
$3l+3)9^3 + 18^2 - 9( 3l^2+3l-3$
$9l^3+9l^2$
------------------- $ \frac{9l^3}{3l} = 3^2$
$9l^2-9$
$9l^2+9l$
----------------------- $\frac{9l^2}{3l} = 3l$
$ -9l-9$
$-9l-9$ $\frac{-9l}{3l} = -3$
-------------------------
0
--------------------------
The quotient is $3l^2+3l-3$ and the remainder is 0.
Advertisements