- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Divide (i) n2 - 2n + 1 by n - 1
Given: n2 - 2n + 1 by n - 1
To find: We have to divide n2 - 2n + 1 by n - 1
Solution:
Factorizing numerator n2 - 2n + 1 by using the identity
x2 - 2xy + y2 = (x - y)2
n2 - 2n + 1 = n2 - 2$\times$n$\times$1 + 12 = (n - 1)2= (n -1)(n - 1)
$\left(\frac{n^{2} \ -\ 2n\ +\ 1}{n-1}\right)$ = $\frac{( n\ -1)( \ n\ -\ 1)}{n-1}$ = n - 1
So$\left(\frac{n^{2} \ -\ 2n\ +\ 1}{n-1}\right)$ = n - 1
Advertisements