Determine the measure of each of the equal angles of a right angled isosceles triangle.
OR
$ABC$ is a right angled triangle in which $\angle A = 90^o$ and $AB = AC$. Find $\angle B$ and $\angle C$.

Given:

$ABC$ is a right angled triangle in which $\angle A = 90^o$ and $AB = AC$.

To do:

We have to find $\angle B$ and $\angle C$.

Solution:

$\angle A = 90^o$

This implies,

$\angle B + \angle C = 90^o$

$\angle B + \angle B = 90^o$                                    (Since $\angle B = \angle C$)

$2\angle B = 90^o$

$\angle B = \frac{90^o}{2} = 45^o$

This implies,

$\angle C = \angle B = 45^o$

Hence, $\angle B = \angle C = 45^o$.

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Updated on: 10-Oct-2022

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