Describe the motion of a body which is accelerating at a constant rate of $10\ ms^{–2}$. If the body starts from rest, how much distance will it cover in $2\ s$ ?

Academic Physics NCERT Class 9

Here in initial velocity $u=0$

Acceleration $a=10\ ms^{-2}$

Time $t=2\ sec.$

Let $s$ be the distance covered by the moving body.

On using the equation of motion $s=ut+\frac{1}{2}at^2$

$s=0\times2+\frac{1}{2}\times10\times2^2$

Or $s=0+20$

Or $s=20\ m$

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Updated on: 10-Oct-2022

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