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Curved surface area of a right circular cylinder is $ 4.4 \mathrm{~m}^{2} $. If the radius of the base of the cylinder is $ 0.7 \mathrm{~m} $, find its height.
Given:
The curved surface area of a right circular cylinder is $4.4\ m^2$.
The radius of the base of the cylinder is $0.7\ m$.
To do:
We have to find its height.
Solution:
The curved surface area of the cylinder $= 4.4\ m^2$
Radius of the base $(r) = 0.7\ m$
Therefore,
Height of the cylinder $=\frac{\text { Curved surface area }}{2 \pi r}$
$=\frac{4.4 \times 7}{2 \times 22 \times 0.7}$
$=\frac{44 \times 7 \times 10}{10 \times 2 \times 22 \times 7}$
$=1 \mathrm{~m}$
The height of the cylinder is $1\ m$.
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