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Construct the angles of the following measurements:
$15^o$
To do:
We have to construct $15^o$.
Solution:
Steps of construction:
(a) Draw a line segment $BC$.
(b) With centre $B$ and a suitable radius, draw an arc meeting $BC$ at $E$.
(c) Cut off arc $EF$ from $E$ and bisect it at $G$.
This implies,
$\angle GBC = 30^o$.
(d) Bisect the arc $EJ$ at $H$.
(e) Join $BH$ and produce it to $A$.
Therefore,
$\angle ABC = 15^o$.
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