Check which of the following are solutions of the equations $2x -y =6$ and which are not.$(\sqrt3, 0)$
Given:
$2x -y =6$
To do:
We have to check whether $(\sqrt3, 0)$ is a solution of the equation $2x -y =6$.
Solution:
To check whether $(\sqrt3, 0)$ is a solution of the equation $2x -y =6$, we have to substitute it in the given equation.
Therefore,
$2(\sqrt3)-0=2\sqrt3$
$≠6$
$(\sqrt3, 0)$ does not satisfy the equation $2x-y=6$.
Hence, $(\sqrt3, 0)$ is not a solution of $2x-y=6$.
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