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By how much will the speed of a body, of fixed mass, increase if its kinetic energy becomes four times its initial kinetic energy ?
As known Kinetic energy $K=\frac{1}{2}mv^2$
Where, $m\rightarrow$ mass of the body
$v\rightarrow$ velocity of the body
Here, if we double the velocity, the velocity becomes $2v$.
Then, Kinetic enrgy $K=\frac{1}{2}m( 2v)^2$
$=4\times\frac{1}{2}mv^2$
Thus, if we double the velocity then the kinetic energy will become four times.
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