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By how much is $-3a + 4b -5c$ greater than $8a + b -6c$?
Given: $-3a + 4b -5c$ and $8a + b -6c$
To find: We have to find by how much is $-3a + 4b -5c$ greater than $8a + b -6c$.
Solution:
$-3a + 4b -5c - ( 8a + b -6c)$
=$ -3a + 4b -5c -8a -b + 6c$
=$-11a + 3b + c$
Therefore, $ -3a + 4b -5c$ is greater than $8a + b -6c by -11a + 3b + c$
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